Question #5cc93 Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer Babette Apr 15, 2017 #x=1/3# #x=-2/3+-i# Explanation: Subtract #13# from both sides #27x^3+27x^2+27x-13=0# This can factored #(3x-1)(9x^2+12x+13)=0# So, #3x-1=0# #3x=1# #x=1/3# #9x^2+12x+13=0# Use the quadratic formula #(-12+-sqrt((12)^2-4(9)(13)))/(2(9))# #(-12+-sqrt(144-468))/18# #(-12+-sqrt(324)i)/18# #-12/18+-(18i)/18# #-2/3+-i# Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 1500 views around the world You can reuse this answer Creative Commons License