Question #c05da

1 Answer
sankarankalyanam
Jan 14, 2018

y = -x+ 6 which is in the form y = mx + c

Explanation:

Slope of line L1 is m_L = tan (45) = 1

Slope of the line L1 perpendicular to L = -1/(m_L) = -1

Equation of L1 with slope -1 and passing through point (6,0) is

y - y1 = m (x - x1)

y - 0 = -1 * (x - 6)

y = -x + 6 which is in the form y = mx + c

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