A #5.57*g# mass of propane was combusted #24.1*g# oxygen gas. Can you represent the reaction by means of an equation, and identify the reagent in deficiency?

1 Answer
Apr 26, 2017

Answer:

So we work out the molar quantities of each reagent.......and interrogate the stoichiometric reaction..........

Explanation:

#C_3H_8(g) + 5O_2(g) rarr 3CO_2(g) + 4H_2O(l)#

#"Moles of propane"=(5.57*g)/(44.1*g*mol^-1)=0.126*mol#

#"Moles of dioxygen"=(24.1*g)/(32.0*g*mol^-1)=0.753*mol#

And thus there is a SLIGHT stoichiometric excess of dioxygen gas. And #C_3H_8# is the reagent in deficiency.

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