Question

Question #97654

Answer 1

`K = 1.6 ×10^32`

Explanation:

`2"H"_2"O"_2 →2"H"_2"O" + "O"_2`

`ΔH^@ = "-196 kJ"`
`ΔS^@ color(white)(l)= "125.65 J·K"^"-1"`

`ΔG^@ = ΔH^@ -TΔS^@ = "-196 000 J" - 400 color(red)(cancel(color(black)("K"))) × "126.65 J"·color(red)(cancel(color(black)("K"^"-1")))`

`= "-196 000 J" - "50 660 J" = "-246 600 J""`

`ΔG^@ = "-RT"lnK`

`lnK = ("-"ΔG^@)/(RT) = -("-246 600" color(red)(cancel(color(black)("J"))))/("8.314 J"color(red)(cancel(color(black)("K"^"-1"))) × 400 color(red)(cancel(color(black)(K)))) = 74.15`

`K = e^74.15 = 1.6 ×10^32`