Question #97654

1 Answer
Apr 30, 2017

Answer:

#K = 1.6 ×10^32#

Explanation:

#2"H"_2"O"_2 →2"H"_2"O" + "O"_2#

#ΔH^@ = "-196 kJ"#
#ΔS^@ color(white)(l)= "125.65 J·K"^"-1"#

#ΔG^@ = ΔH^@ -TΔS^@ = "-196 000 J" - 400 color(red)(cancel(color(black)("K"))) × "126.65 J"·color(red)(cancel(color(black)("K"^"-1")))#

#= "-196 000 J" - "50 660 J" = "-246 600 J""#

#ΔG^@ = "-RT"lnK#

#lnK = ("-"ΔG^@)/(RT) = -("-246 600" color(red)(cancel(color(black)("J"))))/("8.314 J"color(red)(cancel(color(black)("K"^"-1"))) × 400 color(red)(cancel(color(black)(K)))) = 74.15#

#K = e^74.15 = 1.6 ×10^32#