Question #96ae1

1 Answer
Apr 25, 2017

Answer:

Convert mass quantities to moles and divide by respective coefficients of balanced equation. The smaller number is the limiting reagent.

Explanation:

#3H_2 + N_2 -> 2NH_3#

Example: Assume Given 100 #g# of each reactant, what's the limiting reagent?

moles of #H_2 = ((100g)/(2g mol^-1)) = 50# moles & Divide by '3' => #16.7#

moles of #N_2 = ((100g)/(28g mol^-1)) = 3.57# moles & Divide by '1' => #3.57#

The limiting reagent is #N_2# because after dividing by respective coefficients => #3.57# is smaller than #16.7# and #H_2# will be in excess; after all #N_2# is consumed in the reaction.