Question

Question #96ae1

Answer 1

Convert mass quantities to moles and divide by respective coefficients of balanced equation. The smaller number is the limiting reagent.

Explanation:

`3H_2 + N_2 -> 2NH_3`

Example: Assume Given 100 `g` of each reactant, what's the limiting reagent?

moles of `H_2 = ((100g)/(2g mol^-1)) = 50` moles & Divide by '3' => `16.7`

moles of `N_2 = ((100g)/(28g mol^-1)) = 3.57` moles & Divide by '1' => `3.57`

The limiting reagent is `N_2` because after dividing by respective coefficients => `3.57` is smaller than `16.7` and `H_2` will be in excess; after all `N_2` is consumed in the reaction.