A #9.95*mol# quantity of ideal gas is placed in a container of #208*L# volume at #1.26*atm# pressure. What is the temperature of the gas?

1 Answer
Apr 26, 2017

Answer:

We can assume ideality, and find #T~=320*K#

Explanation:

#T=(PV)/(nR)= (1.26*cancel(atm)xx208*cancelL)/(9.95*cancel(mol)xx0.0821*cancel(L*atm)*K^-1*cancel(mol^-1))#

At least this is dimensionally consistent. We wanted an answer in #K#, we got an answer in #1/(K^-1)=1/(1/K)=K# as required............

So two questions:

From where did I get the expression #T=(PV)/(nR)#?

If we had measured #"ammonia gas"# or #"hydrogen chloride"# would our assumption of ideality be justified?