If there are #56*L# of ozone, what molar quantity is present under standard conditions?

1 Answer
anor277
Apr 25, 2017

Well, if it is pure ozone, there are approx. #2.5*mol# of #O_3(g)#.

Explanation:

Under standard conditions of temperature and pressure, #273*K#, and #1*atm#, one mole of ideal gas occupies #22.4*L#.

And thus we calculate the quotient..........

#(56*L)/(22.4*L*mol^-1)=??*mol#

Note that ozone is a trace atmospheric gas, and you cannot get a bottle of ozone, as you would get a bottle of dioxygen, dinitrogen, etc.

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