# Question 8b42e

Apr 27, 2017

Mostly not possible.........................

#### Explanation:

This is a very hard question and I think no one could solve this question because this is listed in the list of unsolved questions in physics.

Free neutrons are unstable with a half life of 10 minutes,11 seconds .It decays via beta decay$\left({\beta}^{-} \text{decay}\right)$

Beta Decay

Beta decay is a very complicated process and involves one of the fermions,upp quarks and down quarks

As you must know a neutron is made 2 down quarks and 1 upp quark

A free neutron is not stable. The upp quark in the neutron get converted into a down neutron and a W boson. This can be represented in an equation

$\text{udd" rarr "uud} + W b o s o n$

Obtaining from this equation

$u \rightarrow \text{W boson}$

This means the weight of W boson

Mass of upp quark = 2.15 mega electron volts

1 $\text{MeV} = 1.6 \times {10}^{- 19} J$

$\therefore$ $2.15 M e V = 2.15 \times \left(1.6 \times {10}^{- 19} J\right)$

= $3.44e-19 J$

$E = m {c}^{2}$

c is speed of light

We know the energy calculate the mass

$3.44e-19 = {\text{299,792,458/s}}^{2} x$

Calculate x

$1.1474605e-27 k g$

Some others say 2.4572e-22 kg

$\therefore$ Mass of W Boson = 2.4572e-22 kg - "mass of down quark" #

The W boson later decays to form an antineutrino and a electron

$\text{W boson" rarr "antineutrino" + "electron}$

So you can say neutrons can't say stable.After 2 neutrons being bonded there are no trineutrons nor tetraneutron and Pentaneutron.