If a #2.96*g# mass of potassium chloride, and a #1.92*g# mass of dioxygen gas react, what mass of #"potassium chlorate"# results?

1 Answer
Apr 29, 2017

Answer:

#x<=............5*g#

Explanation:

There are #x*g# #KClO_3#...........

And we recover #(2.96*g)/(74.55*g*mol^-1)=0.0397*mol# with respect to #KCl#.

And #(1.92*g)/(15.999*g*mol^-1)=0.120*mol# with respect to #"oxygen"#.

Clearly, there were #0.0397# #"mol"# with respect to #KClO_3#.

And thus #x#, #"mass of potassium chlorate"# #=# #0.0397*molxx122.55*g*mol^-1=4.86*g#