# If a 2.96*g mass of potassium chloride, and a 1.92*g mass of dioxygen gas react, what mass of "potassium chlorate" results?

Apr 29, 2017

#### Answer:

$x \le \ldots \ldots \ldots \ldots 5 \cdot g$

#### Explanation:

There are $x \cdot g$ $K C l {O}_{3}$...........

And we recover $\frac{2.96 \cdot g}{74.55 \cdot g \cdot m o {l}^{-} 1} = 0.0397 \cdot m o l$ with respect to $K C l$.

And $\frac{1.92 \cdot g}{15.999 \cdot g \cdot m o {l}^{-} 1} = 0.120 \cdot m o l$ with respect to $\text{oxygen}$.

Clearly, there were $0.0397$ $\text{mol}$ with respect to $K C l {O}_{3}$.

And thus $x$, $\text{mass of potassium chlorate}$ $=$ $0.0397 \cdot m o l \times 122.55 \cdot g \cdot m o {l}^{-} 1 = 4.86 \cdot g$