Question ca019

Apr 30, 2017

It undergoes heterolytic fission whereby the Cl atom gains both the shared electrons.

Explanation:

In aqueous medium, $H C l$ dissociates to form ${H}^{+}$ and $C {l}^{-}$ ions. This happens when the covalent H-Cl bond breaks.

Reaction of $H C l$ with $N a O H$ will give $N {a}^{+} + C {l}^{-} + {H}_{2} O$.

Apr 30, 2017

Well, it breaks..............

Explanation:

We would describe the bond in hydrogen chloride as polar covalent, i.e. ""^(+delta)H-Cl^(delta-)#. Now hydrogen chloride is a room temperature gas, but the gas is VERY soluble in water to give hydrochloric acid, in which ionization is conceived to have occurred:

$H - C l \left(g\right) + {H}_{2} O \left(l\right) \rightarrow {H}_{3} {O}^{+} + C {l}^{-}$

And we could represent the reaction of hydrogen chloride with sodium hydroxide as:

$H C l \left(a q\right) + N a O H \left(a q\right) \rightarrow N a C l \left(a q\right) + {H}_{2} O \left(l\right)$

In aqueous solution, the $\left(a q\right)$ represents the aquated ion, i.e. $N {a}^{+} \left(a q\right) \equiv {\left[N a {\left(O {H}_{2}\right)}_{6}\right]}^{+}$.