If #"10 g"# of #"AlCl"_3"# decomposes, how many grams of #"Cl"_2"# will be produced?
This is a stoichiometry problem.
First, you need to find the number of moles of aluminum chloride.
moles = mass/rmm
Since the equation states that for every 3 molecules of aluminum chloride, you produce 2 molecules of chlorine, by cross-multiplying the amount of moles, you obtain 0.1125 moles of chlorine produced.
Now, just convert moles to grams by rearranging the formula earlier, and you should obtain 7.98 grams (rounded to 2 decimal places)
The process for solving this problem is:
The molar masses of aluminum chloride and chlorine gas must be determined. Molar mass is determined by multiplying the subscript of each element by its atomic weight (relative atomic mass) from the periodic table in grams/mole, or g/mol.
(I will round to the correct number of significant figures at the end.
Multiply the given mass of