# Question #cd974

##### 1 Answer

Feb 4, 2018

The solution is

#### Explanation:

We have:

#log(x - 1)(8 - x) < 1#

#log(-x^2 - 8 + x + 8x) < 1#

#log(-x^2 + 9x - 8) < 1#

Since the log is assumed to be base

#-x^2 + 9x - 8 < 10^1#

#0 < x^2 - 9x + 18#

Solve as an equation and use test points.

#0 = x^2 - 9x + 18#

#0 = (x -6)(x - 3)#

#x= 6 or x = 3#

Clearly

Hopefully this helps!