Question #aa31d

1 Answer
May 2, 2017

Answer:

The concentrations of #"HCl"# and of #"NaCl"# are each 0.08 mol/L.

Explanation:

When you mix the two solutions, the new volume for each component becomes

#"10 mL + 50 mL = 60 mL"#

You can use the dilution formula

#color(blue)(bar(ul(|color(white)(a/a)c_1V_1 = c_2V_2color(white)(a/a)|)))" "#

to calculate the new concentrations.

#c_2 = c_1 × V_1/V_2#

Concentration of #"HCl"#

#c_2 = "0.5 mol/L" × (10 color(red)(cancel(color(black)("mL"))))/(60 color(red)(cancel(color(black)("mL")))) = "0.08 mol/L"#

Concentration of #"NaCl"#

#c_2 = "0.1 mol/L" × (50 color(red)(cancel(color(black)("mL"))))/(60 color(red)(cancel(color(black)("mL")))) = "0.08 mol/L"#