# Question aa31d

May 2, 2017

The concentrations of $\text{HCl}$ and of $\text{NaCl}$ are each 0.08 mol/L.

#### Explanation:

When you mix the two solutions, the new volume for each component becomes

$\text{10 mL + 50 mL = 60 mL}$

You can use the dilution formula

$\textcolor{b l u e}{\overline{\underline{| \textcolor{w h i t e}{\frac{a}{a}} {c}_{1} {V}_{1} = {c}_{2} {V}_{2} \textcolor{w h i t e}{\frac{a}{a}} |}}} \text{ }$

to calculate the new concentrations.

c_2 = c_1 × V_1/V_2#

Concentration of $\text{HCl}$

${c}_{2} = \text{0.5 mol/L" × (10 color(red)(cancel(color(black)("mL"))))/(60 color(red)(cancel(color(black)("mL")))) = "0.08 mol/L}$

Concentration of $\text{NaCl}$

${c}_{2} = \text{0.1 mol/L" × (50 color(red)(cancel(color(black)("mL"))))/(60 color(red)(cancel(color(black)("mL")))) = "0.08 mol/L}$