What will be the final pH on mixing 50 ml of 0.01 M methanoic acid with 50 ml of 0.01 M sodium hydroxide ?
#pK_a# for methanoic acid is 3.75.
From the equation you can see that the total moles of NaOH added will also be 0.005.
The volume of 0.1M NaOH added must also be 50 ml at equivalence.
You should be given the
You need the
You get this from:
Now use this expression for the pOH of a weak base:
You get this from an ICE table and assume the dissociation is negligible.