# Given a "molecular formula" of C_4H_8O_2, what is the "empirical formula"?

May 4, 2017

Well the $\text{molecular formula}$ is ${C}_{4} {H}_{8} {O}_{2}$.........

#### Explanation:

And the $\text{empirical formula}$ is the simplest whole number ratio that defines constituent atoms in a species, and thus...................

$\text{empirical formula}$ $=$ ${C}_{2} {H}_{4} O$

The molecular formula is always a whole number multiple of the empirical formula, i.e............

"molecular formula"=nxx{"empirical formula"}.

To what does $n$ equal here?