Question

Question #65a5e

Answer 1

lim `x-(tanx/t^2)` `=0`
`x->0`

Explanation:

I'm not exactly sure where `t` comes from, but it cancels out in the end anyway

`x->0; x-(tanx/t^2)`
`(0)-(tan(0)/t^2)`
`0-((0/1)/t^2)`
`0-(0/t^2)`
`0-(0)`
`0`

If you have a value for `t`, you can graph it and find the limit that way. This graph is if `t=0`. Regardless, (0,0) is always constant.
graph{x-tanx [-25.83, 25.16, -12.34, 13.1]}