Question #9c275

1 Answer
May 7, 2017

Answer:

You can produce 10.1 g of #"Na"_3"PO"_4#.

Explanation:

The balanced equation is

#"3NaOH + H"_3"PO"_4 → "Na"_3"PO"_4 + 3"H"_2"O"#

#"Moles of NaOH"#

#= 1.11 × 10^23 color(red)(cancel(color(black)("formula units NaOH"))) × "1 mol NaOH"/(6.022 × 10^23 color(red)(cancel(color(black)("formula units NaOH")))) = "0.1843 mol NaOH"#

#"Moles of Na"_3"PO"_4 = 0.1842 color(red)(cancel(color(black)("mol NaOH"))) × ("1 mol Na"_3"PO"_4)/(3 color(red)(cancel(color(black)("mol NaOH")))) = "0.061 44 mol Na"_3"PO"_4#

#"Mass of Na"_3"PO"_4 = "0.061 44" "mol Na"_3"PO"_4 × ("163.94 g Na"_3"PO"_4)/(1 "mol Na"_3"PO"_4) = "10.1 g Na"_3"PO"_4#