# Question #8d622

##### 1 Answer

May 8, 2017

#### Explanation:

We have:

# f(x) = 3x^2+3x+2 #

An

# => 3x^2+3x+2 = 0 #

To solve this quadratic we could compete the square or use the quadratic formula,

We can also use the discriminant

If

# Delta=b^2-4ac \ { (lt 0, "no real roots"), (=0, "two equal real roots"), (gt 0, "two distinct real roots") :}#

For our equation we have:

# Delta = 3*3-4*2*2 < 0 #

Hence there are no real solutions, and therefore

We can confirm this graphically:

graph{3x^2+3x+2 [-5, 5, -2, 5]}