# What is the pH of an aqueous solution in which [HO^-]=0.041*mol*L^-1?

May 10, 2017

$p H = 12.6$

#### Explanation:

We know that in aqueous solution under standard conditions.....

$p H + p O H = 14$.

And $p O H = - {\log}_{10} \left[H {O}^{-}\right]$; so here $p O H = - {\log}_{10} \left(0.041\right) =$

$- {\log}_{10} 0.041 = - \left(- 1.39\right) = 1.39$.

And thus $p H = 14 - p O H = 12.6$

So is this solution acid or alkaline?