# A gas enclosed in piston at 328.2*K occupies a volume of 3.60*L. How does the volume change when the gas is cooled to 303.2*K?

May 14, 2017

We use old $\text{Charles' Law............} V \propto T$

#### Explanation:

If $V \propto T$, then $V = k T$; the equation assumes constant pressure, and a given quantity of gas. $T$ is specified as $\text{absolute temperature}$.

If we solve for $k$, the $\frac{V}{T} = k$........

And given constant pressure, a constant quantity of gas:

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

${V}_{2} = \frac{3.60 \cdot L}{328.2 \cdot K} \times 303.2 \cdot K = 3.3 \cdot L$.