A gas enclosed in piston at $328.2K$ occupies a volume of $3.60L$ . How does the volume change when the gas is cooled to $303.2*K$ ?

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Answer 1 · 2017-05-14T08:31:53

We use old $"Charles' Law............"VpropT$

If $VpropT$ , then $V=kT$ ; the equation assumes constant pressure, and a given quantity of gas. $T$ is specified as $"absolute temperature"$ .

If we solve for $k$ , the $V/T=k$ ........

And given constant pressure, a constant quantity of gas:

$V_1/T_1=V_2/T_2$

$V_2=(3.60*L)/(328.2*K)xx303.2*K=3.3*L$ .

A gas enclosed in piston at 328.2*K328.2*K occupies a volume of 3.60*L3.60*L. How does the volume change when the gas is cooled to 303.2*K303.2*K?