Question #6bd15

May 16, 2017

Answer: $6 \sqrt{2}$

Explanation:

Evaluate: $3 \cdot \sqrt{8}$
(Assuming question meant square root)

Note that $\sqrt{{a}^{2}} = a$

We can only take out squares out of a square root, so we first write out the prime factorization of 8 inside the root:
$3 \cdot \sqrt{{2}^{3}}$

We can see that there is one square, ${2}^{2}$, which we can take out:
$3 \cdot 2 \cdot \sqrt{2}$

Now, we can simplify:
$6 \sqrt{2}$