# Question 8f60c

May 18, 2017

Thermometer Y shows a temperature of 24 °Y.

#### Explanation:

To help us work through this problem, I adapted an image of two common thermometer scales.

Ignore the markings on the thermometers and look at the markings outside them.

On Thermometer X,

${T}_{\textrm{b o i l}} - {T}_{\textrm{\mathfrak{e} e z e}} = \text{220 ° - 20 ° = 200 °}$

On Thermometer Y,

${T}_{\textrm{b o i l}} - {T}_{\textrm{\mathfrak{e} e z e}} = \text{120 ° - (-40 °) = 160 °}$

$\text{200 X° = 160 Y °}$

A temperature of 100 °X is 80 X° above the freezing point of water.

80 color(red)(cancel(color(black)("X°"))) × "160 Y°"/(200 color(red)(cancel(color(black)("X°")))) = "64 Y°"#

The temperature is 64 Y° above the freezing point of water.

∴ On Thermometer Y,

$T = \text{-40 ° + 64 ° = 24 °}$

Hence, $\text{100 °X = 24 °Y}$