# How are temperature on Celsius and Kelvin scales related?

Aug 13, 2018

Well, on the Celsius scale....we set $0$ ""^@C $\equiv$ $\text{the normal freezing point of water}$

#### Explanation:

And on the $\text{temperatura assoluta}$ scale, $\text{the normal freezing point of water} \equiv 273.15 \cdot K$...

Here, the $\text{absolute or Kelvin temperature scale}$ sets ZERO at $- 273.15$ ""^@C...the point at which all molecular motion ceases...

Aug 13, 2018

"Temp"("K") = "Temp"(""^@"C") + 273.15

"Temp"(""^@"C") = "Temp"("K") - 273.15

#### Explanation:

${0}^{\circ} \text{C"= "273.15 K}$

$\text{0 K" = -273.15^@"C}$

A change in temperature of $1$ Kelvin is equivalent to a change of ${1}^{\circ} \text{C}$, so they have the same magnitude.

However, the Kelvin scale is based on $\text{0 K} \setminus =$ $\text{absolute zero}$ (the coldest possible temperature where atoms have no thermal movement).

The Celsius scale is based on ${0}^{\circ} \text{C" = "freezing point of pure water}$ (at standard sea-level pressure).

The two scales are related by a difference of $273.15$.

$T \left(\text{K") = T(""^@"C}\right) + 273.15$

$T \left(\text{^@"C") = T("K}\right) - 273.15$