# Question eee3a

May 17, 2017

The substance is most likely iron.

#### Explanation:

It looks as if we should calculate the specific heat capacity of the substance.

The formula for the amount heat $q$ absorbed by a substance is

color(blue)(bar(ul(|color(white)(a/a)q = mCΔTcolor(white)(a/a)|)))" "

where

$m$ is the mass of the substance
$C$ is the specific heat capacity of the material
ΔT is the temperature change

You can rearrange the formula to calculate the specific heat capacity:

C = q/(mΔT)

In this problem,

q = 1.539 × 10^2color(white)(l) "J"
$m = \text{17.1 g}$
ΔT = "(45.0 - 25.0) °C" = "20.0 °C"

C = (1.539 × 10^2color(white)(l) "J")/"17.1 g × 20.0 °C" = "0.450 J·°C"^"-1""g"^"-1"#

The Engineering Toolbox lists the following specific heat capacities of metals:

$\text{Cr = 0.46 kJ/(K·kg)}$
$\text{Fe = 0.45 kJ/(K·kg)}$
$\text{Ni = 0.44 kJ/(K·kg)}$

I will go for the one in the middle and say that the substance is most likely iron.