# Question #27cfc

May 24, 2017

ONE (1)

#### Explanation:

One mole of any gas at 0 deg-Celcius (=273K) and 1 atm pressure (STP) occupies 22.4 Liters.

Using Ideal Gas Law PV = nRT => V = (nRT)/(P)

For Volume of 1 mole of any gas at STP

${V}_{S T P} = \left(\left(1 \text{mole")(0.08206"L-Atm"/"mole-K}\right) \left(273 K\right) \left(1 A t {m}^{- 1}\right)\right) = 22.4 L i t e r s$