# Question #29e41

May 18, 2017

$T = 398.15$ $\text{K}$

#### Explanation:

The relationship between Celsius and Kelvin is given by the following formula:

${T}_{\left(\text{^@ "C""")) = T_(("K}\right)} - 273.15$

We need to convert ${125}^{\circ} \text{C}$ to $\text{K}$.

So let's start by expressing the above equation in terms of ${T}_{\left(\text{K}\right)}$:

$R i g h t a r r o w {T}_{\left(\text{K")) = T_((""^@ "C}\right)} + 273.15$

Then, let's substitute $125$ into the rearranged equation:

$R i g h t a r r o w {T}_{\left(\text{K}\right)} = \left(125 + 273.15\right)$ $\text{K}$

$\therefore {T}_{\left(\text{K}\right)} = 398.15$ $\text{K}$

Therefore, ${125}^{\circ} \text{C}$ is equivalent to $398.15$ $\text{K}$.