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Answer 1 · 2017-05-18T23:12:19

#T = 398.15# #"K"#

The relationship between Celsius and Kelvin is given by the following formula:

#T_((""^@ "C""")) = T_(("K")) - 273.15#

We need to convert #125^@ "C"# to #"K"#.

So let's start by expressing the above equation in terms of #T_(("K"))#:

#Rightarrow T_(("K")) = T_((""^@ "C""")) + 273.15#

Then, let's substitute #125# into the rearranged equation:

#Rightarrow T_(("K")) = (125 + 273.15)# #"K"#

#therefore T_(("K")) = 398.15# #"K"#

Therefore, #125^@ "C"# is equivalent to # 398.15# #"K"#.