Question #7ea96

May 19, 2017

$C {H}_{3} C O O A g \left(a q\right) r i g h t \le f t h a r p \infty n s A {g}^{+} \left(a q\right) + C {H}_{3} C O {O}^{-} \left(a q\right)$

Explanation:

Aqueous silver acetate, which can be written as $C {H}_{3} C O O A g \left(a q\right)$ or $A g {C}_{2} {H}_{3} {O}_{2} \left(a q\right)$, is a weak electrolyte and a highly soluble compound, and it dissociates into $A {g}^{+}$ and $C {H}_{3} C O {O}^{-}$; the equation for its dissociation in water is thus

$C {H}_{3} C O O A g \left(a q\right) r i g h t \le f t h a r p \infty n s A {g}^{+} \left(a q\right) + C {H}_{3} C O {O}^{-} \left(a q\right)$

The right and left arrows symbolize the solution is saturated and the reaction is in a state of equilibrium.