# Question #cbcea

May 21, 2017

${S}_{16} = - 232$
We have ${a}_{n} = 8 , 5 , 2. . .$ where $a = 8$ and $d = - 3$
${S}_{n} = \frac{1}{2} n \left[2 a + \left(n - 1\right) d\right]$
${S}_{16} = \frac{16}{2} \left(2 \left(8\right) + \left(- 3\right) \left(16 - 1\right)\right) = - 232$