Question

If sum of six consecutive integers is `393`, what is the third integer?

Answer 1

Third number is `65`.

Explanation:

Let the six consecutive integers be `x`, `x+1`, `x+2`, `x+3`, `x+4` and `x+5`.

Hence `x+x+1+x+2+x+3+x+4+x+5=393`

or `6x+15=393` or `6x=393-15=378` and `x=378/6=63`

and third number is `63+2=65`.