# If sum of six consecutive integers is 393, what is the third integer?

May 22, 2017

Third number is $65$.

#### Explanation:

Let the six consecutive integers be $x$, $x + 1$, $x + 2$, $x + 3$, $x + 4$ and $x + 5$.

Hence $x + x + 1 + x + 2 + x + 3 + x + 4 + x + 5 = 393$

or $6 x + 15 = 393$ or $6 x = 393 - 15 = 378$ and $x = \frac{378}{6} = 63$

and third number is $63 + 2 = 65$.