# How many oxygen ATOMS are present in a 25*g mass of aluminum phosphate?

May 25, 2017

Approx. $0.82 \times {N}_{A}$ oxygen atoms, where ${N}_{A} = 6.022 \times {10}^{23}$.

#### Explanation:

$\text{Moles of aluminium phosphate} = \frac{25 \cdot g}{121.95 \cdot g \cdot m o {l}^{-} 1}$

$= 0.205 \cdot m o l$

But given the molar quantity, and given the stoichiometry of $A l P {O}_{4}$, there are $4 \times 0.205 \cdot m o l = 0.820 \cdot m o l$ of $\text{oxygen atoms}$, i.e. 0.820*molxx6.022xx10^23*mol^-1=?? oxygen atoms...

What mass of oxygen does this molar quantity represent.