# Given two aqueous solution whose respective pH values are 6 and 3, how much more acidic is one solution compared to the other?

May 25, 2017

$\text{By a factor of 1000.............}$

#### Explanation:

By definition, $p H = - {\log}_{10} \left[{H}_{3} {O}^{+}\right]$......

And thus when $p H = 6$, $\left[{H}_{3} {O}^{+}\right] = {10}^{- 6} \cdot m o l \cdot {L}^{-} 1$

And when $p H = 3$, $\left[{H}_{3} {O}^{+}\right] = {10}^{- 3} \cdot m o l \cdot {L}^{-} 1$.

And thus there is a 1000-fold difference between the solution concentrations with respect to $\left[{H}_{3} {O}^{+}\right]$. AS always, the numerically LOWER $p H$ corresponds to a higher concentration of $\left[{H}_{3} {O}^{+}\right]$. If we have a concentration of $\left[H C l\right] = 1.0 \cdot m o l \cdot {L}^{-} 1$, what is the solution $p H$?

For an undergrad discussion of $p H$ see this linky.