Question

A `60*mL` volume of sodium hydroxide at `0.15*mol*L^-1` concentration is titrated with `0.500*mol*L^-1` `HCl(aq)`. What volume of acid is required?

Answer 1

We use the relationship `C_1V_1=C_2V_2`, where `C_i`, and `V_i` are the individual concentrations/volumes. But FIRST you need a stoichiometric equation. Eventually I gets under `20*mL`.

Explanation:

Here, there is certainly 1:1 stoichiometry between acid and base, i.e.:

`NaOH(aq) + HCl(aq) rarr NaCl(aq) + H_2O(l)`

And please note that the product `C_1V_1="moles"*L^-1xxL`, i.e. an ANSWER in moles as required...........

And so if `C_1V_1=C_2V_2`, then............

`V_2=(C_1V_1)/C_2=(60*mLxx0.15*mol*L^-1)/(0.500*mol*L^-1)=18*mL`