# Question #742bc

May 28, 2017

b. 120'K

#### Explanation:

Start with the Ideal Gas Law: $P \cdot V = \left(n \cdot R \cdot T\right)$
Rearranging the Ideal Gas Law equation we have $T = \frac{P \cdot V}{n \cdot R}$

V = 100.0 L
R = 0.0820575 L-atm/K-mol
28kg = 28000g
n = (28000g/28.0 g/mol) = 1000 moles of ${N}_{2}$.
$P = \left(1 x {10}^{7} P a\right) \cdot \left(\frac{1 \text{atm}}{101325} P a\right)$ = 98.7 atm
$T = \frac{98.7 \cdot 100}{0.0821 \cdot 1000}$ = 120 ‘K