# How is the oxidation of aluminum metal by acid, hydrogen ion, represented?

May 29, 2017

Aluminum is oxidized............

#### Explanation:

$A l \left(s\right) \rightarrow A {l}^{3 +} + 3 {e}^{-}$ $\left(i\right)$

And hydrogen ion is reduced............

${H}^{+} + {e}^{-} \rightarrow \frac{1}{2} {H}_{2} \left(g\right)$ $\left(i i\right)$

And we can cross multiply the individual redox reactions to remove the electrons, which are conceptual particles, i.e. $\left(i\right) + 3 \times \left(i i\right)$:

$A l \left(s\right) + 3 {H}^{+} \rightarrow A {l}^{3 +} + \frac{3}{2} {H}_{2} \left(g\right)$