# How many ATOMS in a 49*g mass of sulfuric acid?

Jun 1, 2017

Approx. $2.1 \times {10}^{24}$ individual atoms.................
We know that in the ONE MOLECULE, the ONE FORMULA UNIT of sulfuric acid, there are 7 atoms: 4xxO;2xxH; $1 \times S$.
We also that know that in a molar quantity of sulfuric acid, i.e. a $98.08 \cdot g$ mass there are ${N}_{A}$ individual formula units, where ${N}_{A} = \text{Avocado's number} = 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$.
And thus number of atoms, $= \text{7"*"atoms"xx(49*g)/(98.08*g*mol^-1)xx6.022xx10^23*mol^-1=??"atoms.....}$