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Answer 1 · 2017-06-01T14:15:23

#37.5^(@)# #"C"#

Let's use Charles' law #frac(V_(1))(T_(1)) = frac(V_(2))(T_(2))#:

#Rightarrow frac(100.0 " ml")(15.0^(@) " C") = frac(250.0 " ml")(T_(2))#

Dividing both sides of the equation by #100.0# #"ml"#:

#Rightarrow frac(1)(15.0^(@) " C") = frac(2.5)(T_(2))#

#Rightarrow T_(2) = 2.5 times 15.0^(@)# #"C"#

#therefore T_(2) = 37.5^(@)# #"C"#

Therefore, the final temperature will be #37.5^(@)# #"C"#.