# Question #aee33

Jun 10, 2017

$\text{46 g Y}$

#### Explanation:

The idea here is that compound $\text{XY}$ will always contain elements $\text{X}$ and $\text{Y}$ in a

$\text{2 g X"/"4 g Y" = "1 g X"/"2 g Y}$

mass ratio. In other words, you will always have $\text{2 g}$ of element $\text{Y}$ for every $\text{1 g}$ of element $\text{X}$ present in the sample.

In your case, you know that the second sample contains $\text{23 g}$ of element $\text{X}$, which means that it must also contain

$23 \textcolor{red}{\cancel{\textcolor{b l a c k}{\text{g X"))) * "2 g Y"/(1color(red)(cancel(color(black)("g X")))) = color(darkgreen)(ul(color(black)("46 g Y}}}}$

I'll leave the answer rounded to two sig figs.