# Question #aee33

##### 1 Answer

Jun 10, 2017

#### Explanation:

The idea here is that compound **always** contain elements

#"2 g X"/"4 g Y" = "1 g X"/"2 g Y"#

mass ratio. In other words, you will **always** have **for every**

In your case, you know that the second sample contains

#23 color(red)(cancel(color(black)("g X"))) * "2 g Y"/(1color(red)(cancel(color(black)("g X")))) = color(darkgreen)(ul(color(black)("46 g Y")))#

I'll leave the answer rounded to two **sig figs**.