Question #393ba

Question

Question #393ba

1 Answer

Impact of this question

1694 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-10T22:58:01

Use $y -intercept$ $y"-intercept"$ and $x -intercept$ $x"-intercept"$ or any two points on the line.

Explanation:

Looking at the equation, it is apparent that it would follow a linear model as there are no exponents or powers (eg $x^{2}$ $x^2$ )

Then what we can do if find to points on the graph and draw a line through these points. The easiest points to find are usually the $y -intercept$ $y"-intercept"$ and $x -intercept$ $x"-intercept"$

The $y -intercept$ $y"-intercept"$ is when $x = 0$ $x=0$ , so to find that point, make $x = 0$ $x=0$ in the equation, and solve for $y$ $y$

$x = 0$ $x=0$

$\Rightarrow - 2 (0) + y = 2$ $=>-2(0)+y=2$

$\Rightarrow y = 2$ $=>y=2$

Hence, when $x = 0$ $x=0$ , $y = 2$ $y=2$ . This represents the point $(0, 2)$ $(0,2)$ . So we should plot this point:

![Geogebra.com]( useruploads.socratic.org )

Then we calculate the other point, the $x -intercept$ $x"-intercept"$

The $x -intercept$ $x"-intercept"$ is when $y = 0$ $y=0$ , so to find that point, make $y = 0$ $y=0$ in the equation, and solve for $x$ $x$

$y = 0$ $y=0$

$\Rightarrow - 2 x + (0) = 2$ $=>-2x+(0)=2$

$\Rightarrow - 2 x = 2$ $=>-2x=2$

$\Rightarrow x = \frac{2}{- 2}$ $=>x=2/-2$

$\Rightarrow x = - 1$ $=>x=-1$

Hence, when $y = 0$ $y=0$ , $x = - 1$ $x=-1$ . This represents the point $(- 1, 0)$ $(-1,0)$ . So we should plot this point with the other point:

![Geogebra.com]( useruploads.socratic.org )

Now join the two points with a straight line:

![Geogebra.com]( useruploads.socratic.org )

And you have the graph of your equation

You can use any two poinst on the line though. The only difference is that instead of finding when $x = 0$ $x=0$ or $y = 0$ $y=0$ , you would find when $x = another number like 3$ $x="another number like "3$ or when $y = another number like 4$ $y="another number like "4$

It is easier to find the $y -intercept$ $y"-intercept"$ and $x -intercept$ $x"-intercept"$ but if you want to challenge yourself, find two points other than the $y -intercept$ $y"-intercept"$ and $x -intercept$ $x"-intercept"$

Science

Math

Humanities

... and beyond

Question #393ba

1 Answer

Explanation:

Related questions

Impact of this question