# Question #1a2c9

##### 2 Answers

#### Answer:

Here's what I got.

#### Explanation:

I'll show you how to find the solubility of potassium chloride and lead(II) nitrate, and leave the solubility of potassium dichromate to you as practice.

The idea here is that the **solubility graph** of a given salt tells you the amount of salt that can be dissolved in a specific volume of *solvent* and at a specific temperature in order to get a **saturated solution**.

In your case, I am assuming that the solubility graph expresses the solubility of three salts in *grams per liter of water*,

So, start by finding the **up** from this point until you reach the

You should find that it lies at a little over **for every** **of water** in order to make a *saturated solution* of potassium chloride.

Since you're trying to dissolve

#"500 g " - " 100 g" = "400 g"#

of **undissolved** salt. One significant figure will suffice here, so the answer will be

Do the same for lead(II) nitrate. Start at the

The way I see it, the value lies right between **for every** **of water**, so

Since the solution can hold a lot more lead(II) nitrate than you're trying to dissolve, i.e. **all the mass** of lead(II) nitrate will dissolve in this solution.

In other words, you will be left with **undissolved** lead(II) nitrate.

#### Answer:

Here's what I get.

#### Explanation:

For each salt, we find 40 °C on the *x*-axis and go straight up until we hit the graph for that salt.

The solubility of

If we add 500 g of

The amount of solid

The solubility of

If we add 500 g of

The amount of solid

The solubility of

If we add 500 g of

The amount of solid