What is the molarity of concentrated nitric acid that has #rho=1.41*g*mL^-1#, and is #70%# concentrated, #"m/m"#?

1 Answer
anor277
Jun 11, 2017

#"Concentration"~=16*mol*L^-1#

Explanation:

We want the expression #"Moles"/"Volume of solution"#, and if we take a #1*mL# volume of nitric acid, with a mass of #1.41*g#, then......

#"Concentration"="Moles"/"Volume"# And we use the percentage and density to find the actual mass of nitric acid solute in (for instance) a #1*mL# volume.

#=((70.0%xx1.41*g)/(63.01*g*mol^-1))/(1*mLxx10^-3*L*mL^-1)=??*mol*L^-1#.

Related questions
See all questions in Molarity
Impact of this question
5362 views around the world
You can reuse this answer
Creative Commons License