# What is the molarity of concentrated nitric acid that has rho=1.41*g*mL^-1, and is 70% concentrated, "m/m"?

Jun 11, 2017

$\text{Concentration} \cong 16 \cdot m o l \cdot {L}^{-} 1$
We want the expression $\text{Moles"/"Volume of solution}$, and if we take a $1 \cdot m L$ volume of nitric acid, with a mass of $1.41 \cdot g$, then......
$\text{Concentration"="Moles"/"Volume}$ And we use the percentage and density to find the actual mass of nitric acid solute in (for instance) a $1 \cdot m L$ volume.
=((70.0%xx1.41*g)/(63.01*g*mol^-1))/(1*mLxx10^-3*L*mL^-1)=??*mol*L^-1.