What mass of sodium hydroxide would be equivalent to a #20*mL# volume of acetic acid, for which #rho_"HOAc"=1.049*g*mL^-1#?

1 Answer
Jun 12, 2017

Answer:

We need a stoichiometric equation.........

Explanation:

#"NaOH(aq)" + "H"_3"CCO"_2"H(l)" rarr "H"_3"CCO"_2^(-)"Na"^(+) + "H"_2"O(l)"#.

This is a #"1:1 reaction"#, and we have to use the density of acetic acid to find the molar equivalence.

This site reports that #rho_"HOAc"=1.049*g*mL^-1#.

And thus #"Moles of HOAc"=(20*mLxx1.049*g*mL^-1)/(60.05*g*mol^-1)#

#=0.349*mol#

And thus an equivalent quantity of #NaOH-=0.349*molxx40.0*g*mol^-1=13.98*g#; of course we would put this mass into aqueous solution first.