# Question #f228f

Jun 16, 2017

${C}_{8} {H}_{8} {O}_{3}$

#### Explanation:

Empirical Formula of Vanillin

Jun 16, 2017

${C}_{8} {H}_{8} {O}_{3}$

#### Explanation:

AS with all these problems, we assume a $100 \cdot g$ mass of unknown compound and work out the molar quantities of each element....

$\text{Moles of carbon} = \frac{63.15 \cdot g}{12.011 \cdot g \cdot m o {l}^{-} 1} = 5.26 \cdot m o l$.

$\text{Moles of hydrogen} = \frac{5.30 \cdot g}{1.00794 \cdot g \cdot m o {l}^{-} 1} = 5.26 \cdot m o l$.

$\text{Moles of oxygen} = \frac{31.55 \cdot g}{15.999 \cdot g \cdot m o {l}^{-} 1} = 1.97 \cdot m o l$.

We divide thru by the smallest molar quantity to give a trial empirical formula of........

${C}_{2.67} {H}_{2.67} {O}_{}$, but if we multiply this by 3 we get..........$\text{whole numbers as required. }$

$\ldots \ldots \ldots \ldots \ldots \ldots \ldots . {C}_{8} {H}_{8} {O}_{3}$