Question #098cc

1 Answer
Doc048
Jun 20, 2017

#V_"eq"# = 16.7 ml of 0.15M HCl

Explanation:

#NaOH + HCl => NaCl + H_2O# has a 1 to 1 reaction ratio. This means that the moles of NaOH neutralized equals the moles of HCl added at the equivalence point ( or, end point ).

=> moles NaOH = moles HCl
=> #(MolarityxxVolume)_"NaOH"# = #(MolarityxxVolume)^ "HCl"#
=> (25 ml)(0.10M NaOH) = V(HCl) x (0.15M HCl)
=> V(HCl) = [(23 ml)(0.10M)]/ [0.15M] = 16.7 ml

Related questions
See all questions in Titration Calculations
Impact of this question
1296 views around the world
You can reuse this answer
Creative Commons License