Question

Question #253f8

Answer 1

`lambda=0.3590 m=3.590xx10^-1 m`

Explanation:

c = `lambda`v

c is the speed of light in meters/second, a constant `3.00xx10^-8`
`lambda` is wavelength of the electromagnetic wave in meters (what we want)
v is the frequency in 1/s or `s^-1`

Convert 835.6 MHz to Hz. There are `10^6` Hz in 1 MHz.
`835.6 cancel(MHz) xx (10^6Hz)/(1cancel(MHz))=8.356xx10^8Hz`

Plug what you know into the equation.

`3.00xx10^8m/s=lambda*8.356xx10^8s^-1`

`(3.00xx10^8m/cancel(s))/(8.356xx10^8cancel(s^-1))=lambda=0.3590=3.590xx10^-1 m`