# Question #14cfe

Jun 24, 2017

AS $\frac{a}{v} ^ 2$ is added with P, the pressure .This term $\frac{a}{v} ^ 2$ will have unit of pressure.
Again $v$ is the molar volume . so unit of $v$ may be $L m o {l}^{-} 1$

If the unit of pressure $P$ is taken as $a t m$, then unit of a will be

$\text{Unit of a"="Unit of "Pxx "Unit of } {v}^{2} = a t m {L}^{2} m o {l}^{-} 2$

If the unit of pressure $P$ is taken as $P a = N {m}^{-} 2$ and unit of molar volume as ${m}^{3} m o {l}^{-} 1$, then unit of a will be

$\text{Unit of a"="Unit of "Pxx "Unit of } {v}^{2}$

$= N \times {m}^{-} 2 {m}^{6} m o {l}^{-} 2$

$= N \times {m}^{4} m o {l}^{-} 2$