Why does sqrt(x^6) not equal x^3?

Jun 30, 2017

See an explanation below:

Explanation:

$\sqrt{{x}^{6}} = \left\mid {x}^{3} \right\mid$ not ${x}^{3}$

An example would be substituting $- 2$ for $x$:

$\sqrt{- {2}^{6}} = \sqrt{64} = 8$

$\left\mid - {2}^{3} \right\mid = \left\mid - 8 \right\mid = 8$

$- {2}^{3} = - 8$