# If 6*g urea is dissolved in 1*L of water, what is the resultant concentration?

Well $\text{concentration}$ $=$ $\text{Moles of solute"/"Volume of solution}$
And urea $O = C {\left(N {H}_{2}\right)}_{2}$ has a molar mass of $60.06 \cdot g \cdot m o {l}^{-} 1$.
And thus $\left[O = C {\left(N {H}_{2}\right)}_{2}\right] = \frac{\frac{6 \cdot g}{60.06 \cdot g \cdot m o {l}^{-} 1}}{1 \cdot L} = 0.010 \cdot m o l \cdot {L}^{-} 1$.