# Question #1a8ba

Jul 4, 2017

$\text{_96^246"Cm" + ""_6^12"C" → ""_102^254 "No" + 4""_0^1"n}$

#### Explanation:

You can find the atomic numbers of curium and nobelium in any Periodic Table.

Then, all you have to remember is that the sums of the subscripts and superscripts must be the same on each side of the reaction arrow.

Thus,

$\text{96 + 6 = 102 + 4×0}$

and

$\text{246 + 12 = 254 + 4×1}$