# Question #a672c

Jul 6, 2017

${29}^{\text{o""C}}$

${36}^{\text{o""C}}$

#### Explanation:

To convert a temperature from Kelvin to Celsius, we can use the equation

$\text{^"o""C" = "K} - 273$

Simply put, just subtract $273$ from the Kelvin value.

We have then

${T}_{1} = 302$ $\text{K}$ $- 273 = {29}^{\text{o""C}}$

${T}_{2} = 309$ $\text{K}$ $- 273 = {36}^{\text{o""C}}$