Question #7e98d

1 Answer
Jul 13, 2017

Answer:

#0.49# #"mol S"#

Explanation:

Note: I'll assume by the term "gram atom" you mean mole.

We're asked to find the number of moles of #"S"# in #48# #"g H"_2"SO"_4#.

We can solve this problems in a few steps:

  1. Convert the given mass of #"H"_2"SO"_4# to moles (using its molar mass)

  2. Convert the moles of #"H"_2"SO"_4# to moles of #"S"#)

Step 1.

We convert the given mass (#48# #"g H"_2"SO"_4#) to moles using the molar mass of #"H"_2"SO"_4#.

The molar mass is

#(2)overbrace((1.01color(white)(l)"g/mol"))^"hydrogen molar mass" + (1)overbrace((32.07color(white)(l)"g/mol"))^"sulfur molar mass" + (4)overbrace((16.00color(white)(l)"g/mol"))^"oxygen molar mass"#

#= color(red)(98.08# #color(red)("g/mol"#

Now converting grams to moles:

#48cancel("g H"_2"SO"_4)((1color(white)(l)"mol H"_2"SO"_4)/(98.08cancel("g H"_2"SO"_4))) = color(green)(0.489# #color(green)("mol H"_2"SO"_4#

Step 2.

Now we recognize that for every molecule of sulfuric acid, there is one atom of sulfur, so we end up with the same number:

#color(green)(0.489)cancel(color(green)("mol H"_2"SO"_4))((1color(white)(l)"mol S")/(1cancel("mol H"_2"SO"_4)))#

#= color(blue)(0.49# #color(blue)("mol S"#

rounded to #2# significant figures.